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**1. Work:**

Work is defined as the amount of job assigned or the amount of job actually done.

**2. Important Formulae**

**2.1. Work from Days**

If A can do a piece of work in n days, then A's 1 day's work =1/*n*

**2.2**

If A's 1 day's work =1/*n*

, then A can finish the work in n days.

**2.3. Ratio**

**1.** If A is thrice as good a workman as B, then:

**(i)** Ratio of work done by A and B =3:1.

**(ii)** Ratio of times taken by A and B to finish a work =1:3

**(iii)** If A is *x* times as good a workman as B, then he will take (1/*x*)*th*

of the time by B to do the same work.

**Some important conclusions:**

**1.** A and B can do a piece of work in 'x' days and 'y' days respectively, then working together, they will take = ”*xy**/x*+*y*” days.

in one day both will finish (*x*+*y/xy*)* ^{th }*part of work.

2. If A , B and C separately can do a work in x , y and z days respectively, the number of days required by them to complete the whole work are= xyz/(xy+yz+zx) days.

3. If A and B together can do a work in ‘x’ days and one of them completes the same amount of work in ‘y’ days. Then another one will take = xy/y-x days to complete the same work.

4. If x_{1} persons , working t_{1} hours everyday, finishes w_{1} amount of work in n_{1} days. While x_{2} persons , working t_{2} hours everyday, finishes w_{2} amount of work in n_{2} days then

“x_{1}t_{1}n_{1}w_{2} = x_{2}t_{2}n_{2}w_{1}”.

5. If “A” number of persons can complete a work in “D” days, if there was “a” number of less persons than it would take “d” more days to finish the work.

Then Ad = a(D+d).